Chapter 6

Organic Chemistry

Section 1   Section 2   Section 3   Section 4

Section 5   Section 6   Section 7   Section 8

Section 9   Section 10

 

Part I:  Organic Compounds:  Alkanes

  bulletSECTION 6.1 Carbon: The Element of Organic Compounds

 

1.  All organic compounds have one characteristic in common, they contain carbon.

 

Name the element that all organic compounds contain.

 

2.  Due to the fact that all organic compounds contain carbon, organic chemistry is the study of carbon-containing compounds.

 

_________ chemistry is the study of carbon-containing compounds.

 

3.  Inorganic chemistry can be defined as the study of individual elements and all noncarbon compounds.  A very few carbon-containing substances are included in inorganic chemistry, such as the carbonates and bicarbonates, carbon dioxide and elemental carbon.

Classify the following compounds as organic or inorganic:

a) KCl

b) CaSO4

c) C6H8O6

d) NaHCO3

e) diamond (pure carbon)

 

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  bulletSECTION 6.2 Organic and Inorganic Compounds Compared

 

4.  Approximately 250,000 inorganic compounds have been identified, while there are more than six million known organic compounds.

 

Inorganic chemistry has (more/fewer) known compounds to study than does organic chemistry.

 

5.  In Table 6.1 note that the normal physical state of organic compounds includes gas, liquids, or solids with low melting points.  However, inorganic compounds are typically solids with very high melting points.

 

Because there are generally (weak/strong) forces acting between molecules, the melting points of most organic substances are low.

 

6.  Other important distinguishing properties between organic and inorganic compounds in Table 6.1 include: their bonding within molecules, their flammability and their solubility in water.

 

Determine whether each of the following statements is describing organic or inorganic compounds.

 

a)     These compounds usually form bonds between “+” and "-" charged ions within molecules.

b)    These compounds are often quite flammable.

c)     These compounds generally have nonpolar bonds, making them insoluble in water.

 

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  bulletSECTION 6.3 Bonding Characteristics and Isomerism

 

7.  There is such a large number of organic compounds for a couple of reasons: first, the bonding characteristics of carbon atoms and second, the isomerism of carbon-containing compounds.

Introducing the Players

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In this chapter we'll be working with three kinds of atoms - carbon, hydrogen and oxygen.  (Figure above).  Notice the black carbon atom has 4 pegs on it arranged in a tetrahedral.  This is because carbon atoms can share 4 electrons with other atoms to complete its octet.  The red oxygen atoms require 2 electrons to complete its octet, that's why there are 2 pegs.  The white hydrogen atoms only need to share one electron; hence, one peg.  The green straws represent a covalent bond consisting of 2 shared electrons.  For our use, the carbon atoms must always have 4 bonds attached to them, the oxygen atoms must have 2 bonds attached to them, and the hydrogens must have one bond attached to them.

Connect the dots, or Tinker Toys 101

Connect 4 carbon atoms together as shown in the following picture:

Click to Enlarge

This is referred to as a carbon skeleton because only the carbon atoms are shown and not any other attached atoms.  This carbon chain can be represented as:

But it is usually represented as:

 

C-C-C-C

 

A) Bonding characteristics of carbon and isomerism of carbon-containing molecules are the reasons for the extremely large number of ________ compounds.

B)  Each carbon atom has _____ bonds attached to it in an organic molecule.

 

8.  Isomerism is a property that simply means two compounds have the same molecular formula but have their atoms arranged differently in structures.

 

When two compounds have different structural arrangements of atoms and yet their molecular formulas are the same, the property of ________ is being demonstrated.

 

9.  Structural isomers are one type of isomerism where the compounds have the same molecular formula, but the atoms are bonded together in different patterns.

Structural Isomers, The Mix 'em up Boys

Construct the molecule above as shown in figure 1 below:

Fig 1

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Structural isomers are basically new molecules that can be built from the same atoms that make up the original molecule.  Build two structural isomers for the molecule above as show in Figure 2 and Figure 3.

   Click to Enlarge  

Fig 2                                              Fig 3

These molecules can be represented as:

 

Is the molecule shown in Figure 4 another different structural isomer of the original molecule?

Fig 4

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No, this is not a different structural isomer.  Is is the same molecule that is shown in Figure 2 above, it has just been flipped over.

 

Which of the structures below represents a structural isomer of the compound shown (choose all that apply):

 

a)       

 

b)      

 

c) 

 

 Check Answers

  bulletSECTION 6.4 Functional Groups – The Organization of Organic Chemistry

 

10.  Organic compounds are classified into families by functional groups, unique combinations of atoms, or structural features.

 

________ ________are one way of distinguishing one family of organic compounds from another.

 

11.  Structural formulas can be written in two formats.  In expanded structural formulas all the covalent bonds in the molecule are shown.  Whereas, in condensed structural formulas only specific bonds are shown (see Example 6.2).

Condensed Formulas and Lazy Chemists

Build the 4 carbon molecule shown in Figure 1.

Fig 1  Click to Enlarge

We can represent this molecule as:

This is the expanded formula for this molecule.  As you can see, it is cumbersome to draw out.  Being lazy, chemists have developed short-hand (condensed) ways of representing the same molecule.  The most common way would be:

CH3CH2CH2CH3

This tells us that we have a 4 carbon chain with a hydrogen atom on each of the "blank bonds" as shown in figure 2.  The condensed formula tells us that the first carbon atom of the chain has 3 hydrogens attached to it, the second has 2 hydrogens attached, etc.

Fig 2  Click to Enlarge

A very lazy chemist would represent the molecule as C4H10, which basically deconstructs the entire molecule and doesn't give us any information on how the atoms are actually put together (figure 3).

Fig 3  Click to Enlarge

 

Identify each of the following as an expanded or a condensed structural formula:

 

       a) 

 

 

      b)

 
 
       c) 
 
 
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  bulletSECTION 6.5 Alkane Structure

 

12.  The simplest of all organic compounds are hydrocarbons which contain only hydrogen and carbon atoms.

 

________ are organic compounds that contain only hydrogen and carbon.

 

13.  Hydrocarbons in which every carbon atom is bonded to four other atoms by single bonds are known as saturated hydrocarbons, or alkanes (see Figure 6.2).

How do you say "I'm Full"?

Fig 1

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Construct the carbon skeleton shown in figure 1.  This carbon skeleton could be represented by the structural formulas:

Now fill in the "blank bond" with hydrogen atoms to get figure 2.

Fig 2

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A) How would you represent this molecule using condensed structural formulas?

B)  Is this compound a saturated hydrocarbon?

   Model Answers:

Identify the alkanes (saturated hydrocarbons) in the diagrams below:

 

 

          a) 

 

 

 

          b) 

 

 

 

          c) 

 

 

14.  The general formula used to represent alkanes is CnH2n+2 where “n” represents the number of carbon atoms in the molecule.

 

a) Using the formula given above, how many hydrogen atoms would there be in an alkane molecule containing four carbon atoms?  Write the molecular formula for this four-carbon alkane.

b) How many hydrogen atoms are needed to complete the following structure?

            

 

15.  “Normal alkanes” refer to those alkanes in which all carbon atoms are lined up in one continuous chain.  In “branched alkanes”, at least one carbon is not part of the continuous chain.

 

Identify each of the following as a “normal” or “branched” alkane.

 

          a) 

 

          b)  CH3-CH2-CH3

 

          c) 

 

 

 

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  bulletSECTION 6.6 Conformations of Alkanes

 

16.  The single bonds within an alkane are capable of rotating, much like a wheel rotates on its axle.  Due to this rotational ability, molecules can exist in many different orientations, called conformations (see Figures 6.7 and 6.8).

The Twists and Turns of Conformations

C-C-C-C-C-C-C

Make the 7 carbon chain represented above and shown in figure 1.

Fig 1

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Notice the bonds linking the carbon atoms allow the chain to freely rotate and twist.  If we twist the chain 180o at the bond where the arrow is located, we get figure 2.

Fig 2

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Which can be represented as: 

By twisting the bonds some more, we can make the molecule look like figure 3.

Fig 3

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Which can be represented as: 

These are different conformations of the same 7 carbon molecules.  By playing around with your model, you can see that many conformations of this model can be made, including:

The main thing is that we always have the same 7 carbon atoms attached to each other in a continuous chain.  Conformations will become very important when naming organic compounds.

 

a)  Alkane molecules can take on different ________ or orientations in space due to the ability of single bonds to rotate.

b)  Which of the following are different conformations of butane, C-C-C-C?

1)

2)

3)

  bulletSECTION 6.7 Alkane Nomenclature

 

17.  Naming organic compounds using a systematic (IUPAC) approach can be fun.  It’s kind of like a code game.  Each name contains a suffix which is unique to the functional group or family of the compound.  The suffix or ending that signifies the alkane family is “-ane”.

 

When naming organic compounds, what ending is used to denote the alkane family?

 

18.  The root of organic compound names comes from the number of carbons that are in the longest chain.  The roots for the first 10 normal hydrocarbons are: C1 = meth-, C2 = eth-, C3 = prop-, C4 = but-, C5 = pent-, C6 = hex-, C7 = hept-, C8 = oct-, C9 = non-, C10 = dec-.  The root and suffix can then be together to name normal hydrocarbons.  For example, an alkane with four carbons would be called butane (see Table 6.3).

 

A six carbon normal alkane would have the name of ________.

 

 

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  bulletSECTION 6.8 Cycloalkanes

 

19.  Alkanes containing rings of carbon atoms are called cycloalkanes.

 

________ are alkanes in which the carbon atoms are in a ring formation.

 

20.  When naming cycloalkanes, IUPAC rules state to place the prefix cyclo- before the regular alkane name (see Table 6.5).

 

Name the following cycloalkanes:

 

          a) 

  

          b) 

c)  What is the total number of hydrogen atoms present in the condensed structural formula shown below?  Remember, each carbon must have 4 bonds connected to it. 

 

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  bulletSECTION 6.9 The Shape of Cycloalkanes

 

21.  When compounds have the same molecular formula and the same structural formula but the atoms take on different spatial arrangements, the compounds are called stereoisomers.

 

Stereoisomers are compounds with the same molecular and ________ formulas but the atoms are in different spatial arrangements.

 

22.  Geometric isomers are a special type of stereoisomer where there are different three-dimensional arrangements of atoms because of restricted rotation around C-C bonds.

 

Geometric isomers are possible with cycloalkanes because there (is/is not) free rotation of the C-C bonds in the ring.

 

23.  There are two types of geometric isomers: cis- and trans- isomers.  Cis-isomers are geometric isomers in which both groups are on the same side of the ring.  In trans-isomers the groups are located on opposite sides (see Figure 6.10).

Ring Around the Rosey With Cycloalkanes

 

Fig 1

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Build the molecule above and as shown in figure 1.  Notice there is no free rotation around the C-C bonds (the carbon atoms cannot spin around) as in the ethane molecule (arrow).  What is the name of this compound?

Answer: cyclopentane

Because the carbon atoms are "locked in place", we can have cis- (same side) and trans- (opposite side) geometric isomers as shown in figure 2.  Which one is cis-?  Which one is trans-?

Fig 2

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Answer:  The left one is trans-, the right one is cis-.

Fig 3

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Construct the molecule above and as shown in figure 3.  Is the molecule cis- or trans-?  How many hydrogen atoms are necessary to complete the molecule?

   Model Answers:

 

Identify each of the following as cis- or trans- isomers:

 

          a) 

 

 

          b) 

 

c) 

 

 

 Check Answers 

  bulletSECTION 6.10 Physical Properties of Alkanes

 

24.  Alkanes contain carbon-carbon and carbon-hydrogen bonds, both of which are nonpolar bonds.  Therefore, alkanes are nonpolar molecules.  Alkanes have lower melting and boiling points than do other organic compounds with similar molecular weight.

 

a) Nonpolar alkane molecules must have (strong/weak) attractive forces between molecules in order to have low melting points.

b)  Can alkanes hydrogen bond with other alkanes?

 

25.  Alkane molecules are nonpolar, whereas water molecules are polar.  Therefore, alkanes are insoluble in water.  The word hydrophobic (“water fearing”) is used to describe molecules or parts of molecules that are insoluble in water.

 

a)  Hydrophobic substances are (soluble/insoluble) in water.

b)  Can alkanes hydrogen bond with water?

 

 

  Section 6.12 The Nomenclature of Alkenes

 

26.  Alkenes are compounds that contain carbon-carbon double bonds and their names end in -ene.  Alkynes contain carbon-carbon triple bonds and their names end in -yne.

 

What family of compounds do the following molecules belong to?

a.   acetylene

b.   CH3CH=CHCH3

c.   1-methyl-3-butyne

d.  

27.  The general formula for alkenes with a single C=C bond is CnH2n where “n” is the number of carbons.

 

a)     In an alkene with six carbons and only one carbon-carbon double bond, how many hydrogen atoms would it contain?

b)    What is the molecular formula for the compound?

c)  What is the total number of hydrogen atoms present in the condensed structural formula shown below?  Remember, each carbon must have 4 bonds connected to it.

C=C-C=C-C

 

28.  Aromatic compounds are those that contain the characteristic benzene ring or its structural relatives.  Benzene (C6H6) has six carbons in a ring arrangement with alternating single and double bonds between the carbon atoms.  It can be represented:

 

                        

   

Compounds that contain a benzene ring are known as ________ compounds.

Section 6.13 The Geometry of Alkenes

29. 

James Double Bond 07

You can make C=C double bonds as shown on the left hand side of figure 1.  You'll notice that you can freely rotate (turn) the carbon atoms in a C-C single bond (shown with arrow on right), but not the carbon atoms in the C=C bond.  C=C bonds "lock" atoms in place so we can have geometric isomers.  In figure 2 is depicted a "trans-" (opposite side) isomer and in figure 3 is shown a "cis-" (same side) isomer, where the green and white balls represent different atoms or groups.

           

Fig 1                         Fig 2                          Fig 3

Click to Enlarge

Another type of condensed formulas just puts the molecule all in a straight line as shown below - just remember each carbon atom must have 4 bonds attached to it.

CH3HC=CHCH3

Construct cis- and trans- isomers for this compound.  Also, draw the isomers in a condensed format that is a bit more expanded than above.

  Model Answers:

                   

 

Identify each of the following as cis- or trans- isomers:

a)

 

b)

c) 

 

30.  In alkenes, if either double-bonded carbon is attached to identical groups, no cis-trans isomers are possible (see Example 6.7).

 

Determine whether each of the following alkenes can exhibit geometric isomerism.  Draw and name the cis- and trans- structural formulas for those that can.

 

a)     H2C=CH-CH3

b)    CH3CH2-CH=CH-Br

c) 

d)  CH3CH=CHCH3

SECTION 6.14 Properties of Alkenes

31.  The physical properties of alkenes are much like those of alkanes; they are nonpolar substances and are therefore insoluble in water but soluble in nonpolar substances.  They are also much less dense than water (see Table 2.2).

 

a)  The majority of compounds in gasoline are medium-length alkane chains.  Will pentene dissolve in gasoline?

b)  Can alkenes hydrogen bond with other alkene molecules?

c)  Can alkenes hydrogen bond with water?

Section 6.16 Aromatic Compounds and the Benzene Structure

32.  When organic compounds do not contain a benzene ring they are referred to as aliphatic compounds or nonaromatic compounds.

 

The aliphatic compounds studied so far are ________, alkenes, and alkynes.

 

33.  Investigations of the benzene ring led to the conclusion that six of the carbon-carbon bonding electrons move freely around the ring in overlapping electron orbitals.  Because of this, the benzene structure is often represented by the symbol

 

 

 

The circle represents the evenly distributed electrons.

 

How many hydrogen atoms (or other groups) can be attached to one of the carbon atoms in the benzene ring?

34.  Although they are different from the aliphatic compounds in many ways, aromatics still have a few things in common with the nonaromatics.  For instance, aromatics are nonpolar and therefore hydrophobic (insoluble in water).

 

As nonpolar compounds, aromatics are insoluble in water and are referred to as ________ substances.

 

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  Section 6.19  Alcohols, Phenols, and Ethers

 

35.  Alcohols have a carbon atom with an attached hydroxyl group (-OH).  Their names end in -ol.

 

Identify the family of compounds that each of the following belong to:

a.  3-pentanol

b.  2-pentene

c.  CH3-CH3

d.  CH3CH2-OH

SECTION 6.21 Physical Properties of Alcohols

36.  The –OH group in alcohols is a polar group capable of hydrogen bonding.  Therefore, small alcohol molecules (i.e. methyl, ethyl, propyl and isopropyl alcohols) are completely soluble in water.  The hydrocarbon portion of alcohols is nonpolar and hydrophobic.  As the length of the hydrocarbon chain increases, the solubility in water decreases because a larger portion of the molecule is hydrophobic (see Figure 6.11, 6.12 and 6.13).

 

a) Which alcohol would be the most soluble in water:

 

          CH3CH2CH2CH2-OH        or      CH3CH2CH2CH2CH2-OH

b) Draw a diagram showing how water would hydrogen bond with CH3-OH.

37.  Alcohol molecules have the ability to hydrogen bond between one another.  This capacity for hydrogen bonding causes alcohols to have much higher boiling points than those of hydrocarbons of comparable molecular weight (see Figure 3.5 and Figure 3.6).

 

a.  Alcohols have ________ boiling points than those of comparable hydrocarbons.

b) Rank the following in terms of increasing boiling points (lowest to highest).

1) CH3-OH

2) CH3CH2CH2-OH

3) CH3CH2CH3

Check Answers

SECTION 6.22 Characteristics and Uses of Phenol

38.  When a hydroxy group is placed on a benzene ring, the resulting compound is a phenol.  A related family of compounds, the phenols, results if the benzene ring has attached groups.

 

Name the chemical family the following structure belongs to:

 

Section 6.23 Ethers

39.  The ether functional group has two carbon atoms bonded to an oxygen atom.  The general formula for an ether is R-O-R’, where the R’ indicates that the two R groups can be the same or different.

The names of ethers have two alkane root names sparated by the term -oxy-.

 

a)  An organic compound in which two carbon atoms are bonded to a single oxygen atom represents the ________ functional group.

b)  How many hydrogen atoms are necessary to complete each of the condensed structures shown below?  Remember, each carbon atom must have 4 bonds attached to it.

1)  C-C-OH

2) 

3)  C-C-O-C

The compound ethoxypropane would be an _____.

40.  Due to the fact that ethers have oxygen atoms, they can hydrogen bond with water.  Therefore, ethers are more water soluble than hydrocarbons, but less than alcohols of comparable molecular weight.

1) CH3CH2-OH     2)    3)  CH2=CH-CH3   

         4)  CH3-O-CH2CH3   5) CH3-CH2-CH3

a)  Identify the functional group in each of the 5 compounds above.

b) Draw how each compound can hydrogen bond to a molecule identical to itself (if possible).

c)  Draw how each compound can hydrogen bond to a water molecule (if possible).

d)  Rank the ability of each of the compounds to dissolve in water, from least soluble to most soluble.

e)  Rank the boiling points of the compounds, from lowest boiling point to highest boiling point.

 

  SECTION 6.24 Thiols

 

41.  Sulfhydryl (-SH) groups are the sulfur counterparts of alcohols.  Compounds with a sulfhydryl group are called thiols. 

 

If the general formula for alcohols is R-OH, the general formula for thiols is ________.

42.  When thiols are oxidized, a coupling reaction occurs (two molecules become one) to form a disulfide (a compound containing an  -S-S- linkage)(see Equation 6.18). 

An -S-S- linkage is called a _____ _____.

 

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 SECTION 6.27 Nomenclature of Aldehydes and Ketones

43.  The carbonyl functional group is an oxygen atom double bonded to a carbon, which is then single bonded to two other atoms.  The carbonyl group is characteristic of both aldehydes and ketones.

 

Name the following functional group: 

44.  When a carbonyl group is bonded to at least one hydrogen, the compound is an aldehyde and the name ends in -al.  Ketones have two carbons bonded directly to the carbonyl group and the name ends in -one.

 

Identify each of the following as an aldehyde or ketone.

a. 

b.  2-butanone

c. 

d.  propanal

 

Section 6.28 Physical Properties of Aldehydes and Ketones

45.  The lack of a hydrogen on the oxygen atom in aldehydes and ketones prevents hydrogen bonding between molecules.  Therefore, the boiling points of aldehydes and ketones are lower than alcohols with similar molecular weights.

 

a) Aldehydes and ketones have boiling points lower than those of alcohols because of the lack of ________.  As pure compounds, aldehydes and ketones (can/cannot) exhibit hydrogen bonding.

b)  Arrange the following in order of increasing boiling points:

1) 1, 5-pentanediol

2) 3-pentanol

3) pentane

4) pentanal

 

 

46.  The difference in electronegativity between carbon and oxygen atoms gives the carbonyl group a polar nature.  The attraction between dipoles of different molecules causes aldehydes and ketones to have higher boiling points than similar molecular weight alkanes.  The polarity of the carbonyl group also means that hydrogen bonding with water molecules is possible.  Therefore, low molecular weight aldehydes and ketones are water soluble.

 

a)     In a carbonyl group, which atom carries a partial positive charge?  A partial negative charge?

 

 

b)    The hydrogens of water molecules are attracted to which atom of the carbonyl group?

c) Diagram how water can hydrogen bond with

d).   1)         2)       3)

1)  Identify the functional group in each of the compounds above.

2)  Draw how each of the compounds can hydrogen bond to a molecule identical to itself (if possible).

3)  Draw how each compound can hydrogen bond to a water molecule (if possible)

4)  Rank the ability of each of the compounds to dissolve in water, from least soluble to most soluble.

5)  Rank the boiling points of the compounds, from lowest boiling point to highest boiling point.

 

Check Answers

   
  SECTION 6.31 The Nomenclature of Carboxylic Acids

47.  Carboxylic acid compounds all have a functional group called a carboxyl group.  Carboxylic acid names end in -ic acid.

 

Which structure(s) can be used to represent the carboxyl group?

a.  -COOH

b. 

c.  -CO2H

Section 6.32 Physical Properties of Carboxylic Acids

48.  Low molecular weight carboxylic acids are liquids at room temperature and are known for their sharp, unpleasant odors.  For instance, butyric acid is a component in perspiration, and that is why locker rooms have “that smell”.

 

Carboxylic acids of ________ molecular weight are liquids at room temperature and have a sharp, unpleasant odor.

 

49.  Carboxylic acids have the highest boiling points of the organic compounds that we have studied.  This is because carboxylic acids can hydrogen bond between molecules creating a structure known as a dimer, where two identical molecules are bonded together.

 

Give the name for the following structure where two identical molecules are bonded together.

50.  Recall that hydrogen bonds are a cohesive force that causes an increase in boiling points of compounds.  Boiling points of carboxylic acids increases with increasing molecular weights.

  1) butanal     2) butane     3) butanoic acid     4) 1-butanol

a)  Identify the functional group in each of the compounds above.

b)  Draw how each compound can hydrogen bond to a molecule identical to itself (if possible).

c)  Draw how each compound can hydrogen bond to a water molecule (if possible).

d)  Rank the ability of each compound to dissolve in water, from least soluble to most soluble.

e)  Rank the boiling points for each of the compounds, from lowest boiling point to highest boiling point.

 

  2) Arrange the following compounds in order of increasing boiling points.

propanoic acid, pentanoic acid, methanoic acid

51.  The ability to hydrogen bond also increases water solubility.  Because of hydrogen bonding, the lower molecular weight carboxylic acids are very water soluble.  Solubility decreases as molecular weight increases.

 

Place the following compounds in order of increasing water solubility:

a)  2-methylhexanoic acid, propanoic acid, and pentanoic acid.

b) ketone, alkane, carboxylic acid, alcohol

SECTION 6.33 Chemical Properties of Carboxylic Acids

52.  A carboxylate ion may be formed from a carboxylic acid when it is dissolved in water (see Reaction 6.30).

 

a) Removing the hydrogen atom from the oxygen on a carboxylic acid creates a ________.

b) Adding a carboxylic acid to water will (raise/lower) the pH of the water.

 

53.  The functional group known as a carboxylic ester is formed when carboxylic acids and alcohols or phenols are heated in the presence of an acid catalyst (see Reaction 6.34).

 

Draw a general structural formula for an ester.

 

54.  The process of forming an ester is known as esterification.

 

The process of ester formation is called ________.

 

55.  In an ester, the single bond between the carbonyl carbon and oxygen is known as the ester linkage.

 

Use an arrow to point to the ester linkage in     

 

56.  Esters can also be formed by reaction of an alcohol and an inorganic acid.  In biochemistry the most important esters of this type are the phosphoric acid esters (see Reaction 6.37).

 

A phosphate ester is produced by the reaction of phosphoric acid and an ________.

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  SECTION 6.35 Classification of Amines

57.  Amines are organic compounds derived from ammonia (NH3) by replacing one or more of ammonia's hydrogen atoms with alkyl or aromatic compounds.

 

Amines are organic compounds that are derived from what inorganic compound?

58.  Amines, like alcohols, can be classified as primary, secondary, or tertiary.  The classifying is done according to how many hydrogens of ammonia (NH3) have been replaced by carbon groups.  For instance, if two carbon groups are bonded to the nitrogen, leaving only one hydrogen, this compound would be classified as a secondary amine (see Table 6.13).

 

Classify each of the following as a primary, secondary, or tertiary amine:

a. 

b. 

c. 

d. 

SECTION 6.36 Physical Properties of Amines

59.  Primary and secondary amines can form hydrogen bonds between themselves just like alcohols.  With amines, the hydrogen bonds form between hydrogen and nitrogen atoms rather than between hydrogen and oxygen atoms as in alcohols.  Hydrogen bonding can also occur between water and amines (see Figure 6.18).

 

Draw structural formulas and indicate with dotted lines where hydrogen bonding can occur between the following molecules.

a)

b)

60.  Because nitrogen is less electronegative than oxygen, the hydrogen bonds formed by amines are weaker than those formed by alcohols.  Therefore, the boiling points of amines are somewhat lower than those of alcohols of similar molecular weights.

 

Place the following compounds in order of increasing boiling point: 1-aminobutane, 2-pentene, 2-butanone, 2-butanol.

61.  Generally speaking, amines with fewer than six carbons are soluble in water as a result of hydrogen bond formation between amine functional groups and water molecules (see Figure 6.18).

 

A) Would you expect 1-aminopentane to be soluble or insoluble in water?

b)      2.  CH3CH2CH2-NH2   3.  CH3CH2CH2-OH

1)  Draw how each of the compounds above can hydrogen bond with a molecule identical to itself (if possible).

2)  Draw how each of the compounds above can hydrogen bond with a water molecule (if possible).

3)  Rank the ability of each compound to dissolve in water, from least soluble to most soluble.

4)  Rank the boiling points for each of the compounds, from lowest boiling point to highest boiling point.

Check Answers

 

bullet SECTION 6.38 Chemical Properties of Amines

 

62.  The characteristic that distinguishes amines as a functional group is that they behave as weak bases because they can accept an H+.  When they react with water they produce hydroxide (OH-) ions.

 

a) Are amines acidic or basic substances?

b) When amines dissolve in water they will (raise/lower) the pH.

 

63.  When amines react with acid chlorides or acid anhydrides a compound known as an amide is formed.

 

________ are formed when amines react with acid chlorides or carboxylic acid anhydrides.

 

Amide functional groups have a carbonyl group attached to a nitrogen.  The single bond linking the carbonyl carbon and nitrogen atoms in the group is called an amide linkage.

 

Draw the amide functional group, labeling the amide linkage.

SECTION 6.39 Physical Properties of Amides

64.  Hydrogen bonding can occur between the amide hydrogens and the carbonyl oxygen in amides (see Figure 6.19).  This intermolecular hydrogen bonding in amides gives them high melting points.  Hydrogen bonding is also responsible for the relatively high water solubility of amides (see Figure 6.20).

 

a)  Show hydrogen bonding by using a dotted line between the following amides:

  

b)  Rank the following in order of increasing hydrogen bond strengths between identical molecules:  alkyne, carboxylic acid, ether, amide, amine

 

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